User blog comment:Fedora Kid/Issues Concering the Wiki's Main Page/@comment-3037915-20110320133804

@TeamMu Let's see, what about [(S-O)+S]/2? So if something had 2 supports and 4 opposes, it's final score would be 0. And if something had 8 supports and 11 opposes, it's final score would be 2.5, making this second one win.

With the system they're using now, something with 2 support and 4 opposes would score -2 and something woth 8 supports and 11 opposes would get a score of -3, making the first one win.

Sorry, I'm bored.